pyspark.sql.functions.regexp_substr

pyspark.sql.functions.regexp_substr(str: ColumnOrName, regexp: ColumnOrName) → pyspark.sql.column.Column

Returns the substring that matches the Java regex regexp within the string str. If the regular expression is not found, the result is null.

New in version 3.5.0.

Parameters

strColumn or str

target column to work on.

regexpColumn or str

regex pattern to apply.

Returns

Column

the substring that matches a Java regex within the string str.

Examples

>>> df = spark.createDataFrame([("1a 2b 14m", r"\d+")], ["str", "regexp"])
>>> df.select(regexp_substr('str', lit(r'\d+')).alias('d')).collect()
[Row(d='1')]
>>> df.select(regexp_substr('str', lit(r'mmm')).alias('d')).collect()
[Row(d=None)]
>>> df.select(regexp_substr("str", col("regexp")).alias('d')).collect()
[Row(d='1')]

previous

pyspark.sql.functions.regexp_replace

next

pyspark.sql.functions.regexp_instr